2x^2-24x-5040=0

Solution for 2x^2-24x-5040=0 equation:

2x^2-24x-5040=0

a = 2; b = -24; c = -5040;
Δ = b2-4ac
Δ = -242-4·2·(-5040)
Δ = 40896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40896}=\sqrt{576*71}=\sqrt{576}*\sqrt{71}=24\sqrt{71}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24\sqrt{71}}{2*2}=\frac{24-24\sqrt{71}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24\sqrt{71}}{2*2}=\frac{24+24\sqrt{71}}{4}
$